(y^2-y-12)/(4y)/(y-4)/8

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Solution for (y^2-y-12)/(4y)/(y-4)/8 equation: 


D( y )

4*y = 0

y-4 = 0

4*y = 0

4*y = 0

4*y = 0 // : 4

y = 0

y-4 = 0

y-4 = 0

y-4 = 0 // + 4

y = 4

y in (-oo:0) U (0:4) U (4:+oo)

(((y^2-y-12)/(4*y))/(y-4))/8 = 0

(y^2-y-12)/(4*8*y*(y-4)) = 0

y^2-y-12 = 0

y^2-y-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)+1)/(1*2) or y = (1-49^(1/2))/(1*2)

y = 4 or y = -3

(y+3)*(y-4) = 0

(y+3)/(4*8*y) = 0

y+3 = 0 // - 3

y = -3

y = -3

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